📝 Chapter 2: Permutations

Assessment OF Learning — Unit Test
✅ Graded — Counts Toward 70% Term Mark
⏱️ Duration: 75 minutes  |  Total: /60 marks
Show all work. Answers without supporting work will receive partial credit at best.
K/U
/15
Thinking
/15
Comm.
/15
Applic.
/15
Part A: Knowledge & Understanding [15 marks]
Question 1 [2 marks]
Evaluate \( 7! - 5! \).
Solution:
\( 7! = 5040 \), \( 5! = 120 \). \( 5040 - 120 = 4920 \).
Question 2 [2 marks]
Compute \( P(9,3) \).
Solution:
\( P(9,3) = 9 \cdot 8 \cdot 7 = 504 \).
Question 3 [2 marks]
How many distinct arrangements of the letters of "BANANA"?
Solution:
6 letters: 3 A, 2 N, 1 B. \( \dfrac{6!}{3!\,2!\,1!} = \dfrac{720}{12} = 60 \).
Question 4 [2 marks]
In how many ways can 9 distinct people sit around a circular table?
Solution:
\( (9-1)! = 8! = 40\,320 \).
Question 5 [2 marks]
Solve for \( n \): \( P(n,2) = 56 \).
Solution:
\( n(n-1) = 56 \Rightarrow n^2 - n - 56 = 0 \Rightarrow (n-8)(n+7) = 0 \Rightarrow n = 8 \).
Question 6 [3 marks]
A teacher arranges 4 girls and 3 boys in a row. How many arrangements if all girls must sit together?
Solution:
"Glue" 4 girls into 1 unit: 4 units in \( 4! = 24 \) ways. Internal: \( 4! = 24 \). Total: \( 24 \cdot 24 = 576 \).
Question 7 [2 marks]
A 5-character password uses any letter (26) followed by any digit (10), repeated, with no other restriction. How many passwords have exactly 3 letters then 2 digits, with letters distinct and digits distinct?
Solution:
\( P(26,3) \cdot P(10,2) = (26\cdot25\cdot24)(10\cdot9) = 15\,600 \cdot 90 = 1\,404\,000 \).
Part B: Thinking [15 marks]
Question 8 [4 marks]
In how many ways can the letters of "ALGEBRA" be arranged so that the word starts and ends with a vowel? Show your case analysis.
0 words
Question 9 [4 marks]
Determine the number of ways 5 women and 4 men can sit in a row if the men cannot sit next to each other. (Hint: place the women first, then place men in the gaps.)
0 words
Question 10 [4 marks]
In how many ways can 4 couples sit around a circular table if each couple must sit together? Show your reasoning, including how circular permutations interact with the "glue" trick.
0 words
Question 11 [3 marks]
Solve algebraically: \( P(n+1, 2) = 30 \). Show all work and reject any extraneous solutions.
0 words
Part C: Communication [15 marks]
Question 12 [4 marks]
A student claims that the number of arrangements of the letters of "TOOL" is \( 4! = 24 \). Is this correct? Explain the error and provide the correct value.
0 words
Question 13 [4 marks]
Explain in your own words why the number of circular arrangements of \( n \) distinct objects is \( (n-1)! \) and not \( n! \). Use a small example (e.g., \( n = 4 \)) to support your explanation.
0 words
Question 14 [4 marks]
Describe a step-by-step procedure for solving a "permutations with restrictions" problem (e.g., "must be adjacent" or "cannot be adjacent"). Include both the "glue method" and the "complement / gaps" method.
0 words
Question 15 [3 marks]
Compare a permutation and a combination. Give an example of each, and explain how the formulas \( P(n,r) = \dfrac{n!}{(n-r)!} \) and \( C(n,r) = \dfrac{n!}{r!(n-r)!} \) are related.
0 words
Part D: Application [15 marks]
Question 16 [4 marks]
Ontario licence plates have the form ABC 123 (3 letters, then 3 digits). a) How many plates are possible if all are allowed to repeat? b) How many start with the letter "M"?
0 words
Question 17 [4 marks]
A robot must walk on a grid from \( (0,0) \) to \( (5,3) \), making only right (R) and up (U) moves. How many distinct paths are possible? (This is a permutation-with-identical-objects problem.)
0 words
Question 18 [3 marks]
A baseball coach must select a batting order for 9 players. If two specific players, the captain and the lead-off hitter, must bat 1st and 2nd respectively, how many batting orders are possible?
0 words
Question 19 [4 marks]
A 5-digit password uses digits 0–9. How many passwords are there with: a) all distinct digits, b) at least one repeated digit?
0 words

Evaluation Rubric

LevelDescription%
4Thorough, insightful, high degree of effectiveness80–100%
3Considerable effectiveness (provincial standard)70–79%
2Some effectiveness, approaching standard60–69%
1Limited effectiveness50–59%
RInsufficient achievementBelow 50%