A batch of 50 items contains 8 defective. A sample of 10 is selected. \( P(\text{exactly 2 defective}) \) = ? (Decimal to 4 places)
Solution:
\( P = \dfrac{\binom{8}{2}\binom{42}{8}}{\binom{50}{10}} = \dfrac{28 \cdot 118\,030\,185}{10\,272\,278\,170} \approx 0.2964 \).