Unit 5: Population Dynamics — Unit Test

Assessment OF Learning · Strand F
Graded — Counts Toward 70% Term Mark
Duration: 75 min  |  Total: /60 marks  |  Show all work.
K/U
/15
Thinking
/15
Comm.
/15
Applic.
/15
Part A: Knowledge & Understanding [15 marks]
1
[3]
State the equations for exponential and logistic growth. Define each variable.
Answer Key

Exponential: dN/dt = rN; closed form N_t = N₀e^(rt). Logistic: dN/dt = rN(K−N)/K. N = population size; r = intrinsic growth rate; K = carrying capacity; t = time. Logistic includes the term (K−N)/K which approaches 0 as N → K, slowing growth.

2
[2]
Carrying capacity is best defined as:
Answer Key

B. The maximum population size that the environment can sustain indefinitely given resources, predators, disease.

3
[3]
Compare r-selected and K-selected species in a 4-row table: number of offspring, parental care, lifespan, habitat type.
Answer Key

r-selected: many offspring; little or no parental care; short lifespan; unstable/disturbed habitats (e.g., dandelions, mosquitoes). K-selected: few offspring; extensive parental care; long lifespan; stable, predictable habitats (e.g., elephants, oak trees, humans).

4
[3]
Distinguish density-dependent and density-independent regulators. Give two examples of each.
Answer Key

Density-dependent (intensify with crowding): disease, intraspecific competition, predation, parasitism. Density-independent (act regardless of density): drought, hurricane, fire, severe winter, volcanic eruption. Density-dependent factors are stabilizing; density-independent can cause sudden crashes.

5
[2]
Type III survivorship curve indicates:
Answer Key

B. Many young, very high juvenile mortality (e.g., oysters, fish, frogs); only a few survive to reproduce.

6
[2]
Primary succession differs from secondary succession because:
Answer Key

A. Primary: lifeless substrate, requires pioneers (lichens) to build soil → centuries. Secondary: existing soil after disturbance, faster (decades).

Part B: Thinking & Investigation [15 marks]
7
[5]
A bacterial population grows from 200 to 12,800 in 6 hours. (a) Calculate r. (b) Predict N at 12 hours. (c) State an assumption you have made.
Answer Key

(a) N = N₀ e^(rt) → 12,800 = 200 e^(6r) → e^(6r) = 64 → 6r = ln 64 = 4.16 → r ≈ 0.69 hr⁻¹. (b) N(12) = 200 × e^(0.69 × 12) = 200 × e^8.28 ≈ 200 × 3960 ≈ 820,000. (c) Assumption: unlimited resources (exponential model holds, no logistic damping yet).

8
[5]
Calculate Simpson's index of diversity D = 1 − Σp² for two communities: A {60% sp1, 30% sp2, 10% sp3}; B {25% each of 4 species}. Which is more diverse?
Answer Key

A: Σp² = 0.36 + 0.09 + 0.01 = 0.46; D_A = 1 − 0.46 = 0.54. B: Σp² = 4 × 0.0625 = 0.25; D_B = 1 − 0.25 = 0.75. Community B is more diverse — both higher richness (4 species) and even abundance.

9
[5]
A wildlife biologist uses Lincoln-Petersen mark-recapture: 80 deer marked initially; later sample of 100 deer contains 16 marked. Estimate population size and identify three assumptions of the method.
Answer Key

N ≈ (M × C)/R = (80 × 100)/16 = 500 deer. Assumptions: (1) closed population (no births, deaths, immigration, emigration between samples); (2) marks don't fall off or affect survival; (3) each animal equally likely to be captured (no trap-shyness or trap-happiness); (4) marked animals mix randomly with unmarked between samples.

Part C: Communication [15 marks]
10
[5]
Sketch and label exponential vs logistic growth curves on the same axes. Indicate K, lag/exponential/deceleration phases, and where dN/dt is maximum on the logistic curve.
Answer Key

Exponential: J-shape, dN/dt always increasing. Logistic: S-shape (sigmoid). Lag phase (slow start) → exponential phase (steep, rapid growth) → deceleration as N approaches K → plateau at K. Maximum dN/dt occurs at N = K/2 (inflection point). Carrying capacity K shown as horizontal asymptote.

11
[5]
Describe the predator-prey cycle observed between Canada lynx and snowshoe hare. Explain the lag and ecological mechanism.
Answer Key

Hudson's Bay Co. fur-trade records show ~10-year cycles. Hare numbers rise → abundant food for lynx → lynx reproduce, lynx population rises (lagged by ~1–2 years). Heavy lynx predation depresses hare population; hare crash → lynx starve → lynx population crashes. Reduced predation lets hares recover, restarting the cycle. Mechanism: time-lagged density-dependent predation; also vegetation quality and disease contribute.

12
[5]
Describe primary succession on a newly formed volcanic island, listing community changes from pioneer species to climax forest.
Answer Key

(1) Bare lava rock — no soil, no life. (2) Pioneer species: lichens and mosses break rock chemically/mechanically; trapped organic material begins forming soil. (3) Small herbaceous plants (grasses, ferns) colonize thin soil. (4) Shrubs and small trees follow as soil deepens. (5) Hardy fast-growing trees (alder, birch) form early forest. (6) Shade-tolerant climax species (e.g., maple, hemlock) dominate the mature, stable climax community. Process can take centuries.

Part D: Application [15 marks]
13
[5]
Calculation — Doubling Time: Country A has growth rate 1.4% per year; Country B has 3.5%. Use the rule of 70 to estimate doubling times. What does this imply for resource demand?
Answer Key

t_double ≈ 70/r%. A: 70/1.4 = 50 years. B: 70/3.5 = 20 years. Rapidly doubling populations face accelerating resource demand (food, water, housing, energy), strain on infrastructure and services, and increased ecological footprint. Sustainable development requires balancing growth with capacity.

14
[5]
Case — Invasive Species: Zebra mussels (Dreissena polymorpha) entered the Great Lakes via ballast water in the 1980s. Predict initial growth pattern, ecological effects on native species, and one mitigation strategy.
Answer Key

Initial growth: exponential — abundant food (plankton), few predators, no competitors → J-curve. Effects: outcompete native mussels (extirpations); filter-feed plankton, reducing food for fish larvae; clog water intakes, fouling infrastructure (~$ billions); alter clarity, favouring some species over others. Mitigation: ballast-water exchange/treatment regulations; "Clean, drain, dry" boater education; biocontrol research; chemical treatments at intakes.

15
[5]
STSE — Ecological Footprint: Canada's per-capita footprint is ~7.7 gha; world biocapacity is ~1.6 gha/person. Discuss the implications and propose two personal/policy actions to reduce it.
Answer Key

Implication: Canadians use the equivalent of ~5 Earths per capita — unsustainable. Continued at this rate, biodiversity loss, climate change, depletion of fish stocks and forests will accelerate. Personal: reduce meat consumption (esp. beef); use active or public transit; insulate home and switch to heat pump; reduce flights. Policy: carbon pricing; protected areas (e.g., 30 × 30); subsidies for renewables; circular-economy regulations on packaging; investment in transit and densification.